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Last Updated: August 21, 2026
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![Information #240 ll Show that ∃x [C(x) ∧ J(x)] ∧ ∀x [J(x) → H(x)]⇒ ∃x [C(x) ∧ H(x)]. Update](https://i.ytimg.com/vi/6TokX41w99Y/mqdefault.jpg)